A Riddle

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Paul Graupp
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A Riddle

Post by Paul Graupp »

In standard, seven sector displays, what do the digits 4, 5 and 6 have; that the digits
1, 2 & 3 and 7, 8 & 9 do not ??

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Bill Terry
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Post by Bill Terry »

The same number of segments lit as the number represented?

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Paul Graupp
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Post by Paul Graupp »

That's right Bill !! I have never heard this mentioned anywhere and it just struck me one day. I was wondering if anyone else had noticed the coincidence. Good thinking there and keen perception as well ! How long have you known this ??

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Post by Donny Hinson »

That's a good one, Paul! Here's another...

Remember the year 1961? Plug that into your calculator. Now if you rotate the calculator 180 degrees...it still reads 1961.

How soon (what year) will that "curiosity" happen again?
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Post by Paul Graupp »

Donny; I couldn't begin to draw this so I'll have to trust my writing skills....

Three resistors in a straight line, R-1, R-2 and R-3 in series between points A and B. All are 300 ohms. Over the resistors, there is a jumper between point A and the junction of R-2 and R-3 which appears to short out R-1 & R-2. Below the resistors, there is a jumper between the junction of R-1 and R-2 to point B which appears to short out R-2 & R-3.

What is the equivilant resistance of RAB equal to ??

Regards, Paul Image Image Image
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Jim Smith
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Post by Jim Smith »

150 ohms?
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Post by Paul Graupp »

Jim: Sorry, that's not it but you are on the right path.

Donny: The next time that would happen would be at the earliest 14,089 and at the latest, 17059 years from this year. Right ??

Regards, Paul Image Image Image<FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Paul Graupp on 09 August 2002 at 06:53 PM.]</p></FONT>
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Bill Terry
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Post by Bill Terry »

<SMALL>How long have you known this ??</SMALL>
I worked at Tandy Corp. in the mid-90's where I coded 4 and 8 bit microprocessors for answering machines, telephones, etc. In those days we used 7-segment LEDs or LCDs for most displays, and rather than a 7-seg display driver we typically used I/O from the chip and coded our own character set. We always had less pins than we wanted to do the display, key scan, etc. (since less GPI/O = cheaper processors), so I ended up spending a lot of time figuring how to 'light the right segments', make 9k of code fit in 8k ROM, not miss any interrupts, all that stuff.

Somewhere at sometime in that painful process this tidbit of trivia surfaced... Image

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Donny Hinson
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Post by Donny Hinson »

Paul...your answer to my riddle...not quite that long! Try again. Image

In answer to your riddle, 100 ohms. The circuit you describe is actually three 300 ohm resistors in parallel...diagramed to look more complex. Image<FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Donny Hinson on 10 August 2002 at 03:37 AM.]</p></FONT>
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Bob Lawrence
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Post by Bob Lawrence »

The answer is 300 ohms. Taking the path of least resistance current would flow from point A through the jumper located between
R2 and R3 (0 ohms) then through R3 (300 ohms)
to point B. It's still only 9 am what do I do for the rest of the day. Image Image

Bob
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Post by Paul Graupp »

Bob; I'm afraid Donny saw through my smoke screen. Point A looks straight into R-1 and then via the lower jumper, gets to point B.
Via the upper jumper, point A at the junction of R-2 & R-3, looks to the left into R-2 and again throught the lower jumper to point B. To the right it sees R-3 and then directly to point B. So each time it sees a 300 ohm resistor and 300/3=100.

Donny; I must have been sleepy last night but maybe I rushed your riddle a bit. Give me a couple days to see if I can figure some easier solution out...... Image Image Image Image

Regards, Paul
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Joey Ace
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Post by Joey Ace »

Don't you guys have anything better to do than discussing current events ? Image

Here's one I discovered in college, while laying on my back reading an Electronics Testbook:

Print DIODE on a paper, turn the paper over, so it's upside down and wrong side up.

Hold it to a light and you'll see the same word.
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Post by Paul Graupp »

Joey: That's a good one !! Is current like I in E=IxR ?? Nice play on words ! Image Image

Donny: How about 6119 ?? That's closer.....

Regards, Paul Image Image Image Image<FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Paul Graupp on 10 August 2002 at 10:13 AM.]</p></FONT>
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Post by Marty Pollard »

2002
2112
2222
2552
2692
2882
2962
5005
5115
5555
etc.
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Bob Lawrence
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Post by Bob Lawrence »

Paul,

Thanks! I see where I went wrong. This time I had to draw it out. OK, I'm ready for another one.

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Post by Donny Hinson »

Closer, Paul, but no cigar! Actually, Marty is right on track, here. Yes, this (2002) is one of those upside-down years, and probably none of us will be around when it next happens...in 2112. Image
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Post by Paul Graupp »

What is it they used to say, Donny ?? Can't see the forrest for the trees. Image Image Image<FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Paul Graupp on 11 August 2002 at 10:45 AM.]</p></FONT>
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Andy Sandoval
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Post by Andy Sandoval »

Hey can I have some of what you guys are smokin?...just kiddin. I read this thread just out of curiosity and just had to be a smart ass...

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John Daugherty
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Post by John Daugherty »

Looks like you guys have been looking in the ID 10 T file.
Good Grief ...........
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Jay Fagerlie
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Post by Jay Fagerlie »

OK, here's one:



A man is on a boat with a pack of cigarettes and no matches, how did he manage to smoke?


Jay
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Rick Alexander
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Post by Rick Alexander »

He flicked his Bic . . Image
Ray Minich
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Post by Ray Minich »

And here I was lookin' up Norton & Thevenin again... Image

Multiply 12345679 x 8 on yer calculator & see whatcha get.<FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Ray Minich on 05 August 2004 at 11:27 AM.]</p></FONT>
jim milewski
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Post by jim milewski »

did he borrow a light from someone else?
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Jay Fagerlie
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Post by Jay Fagerlie »

He threw a cigarette overboard and made the boat a "cigarette lighter"

HA!

I got that off an old Batman record I had when I was a kid.....

Jay
Paul Graupp
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Post by Paul Graupp »

Ray; My little hand held Radio Shaq calculator only has eight digits but I see what you're saying. Sorta like the square root of 69, ehhh ??

Regards, Paul